document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508254>Question 508254</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One # is twice another, twice the lesser # increase by the greater # is at least 85. Find the least possible value for the lesser # </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340902 by </B><A HREF=/tutors/aboutme.mpl?userid=Comushay><B>Comushay(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Comushay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Comushay><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340902\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Large # - L  = 60<BR>\n" );
document.write( "Small # - s  = 25<BR>\n" );
document.write( " <BR>\n" );
document.write( "  L + S = 85<BR>\n" );
document.write( " -L -2(s)= 10\r<BR>\n" );
document.write( "\n" );
document.write( "(L-L) + s-(-2s) = 85-10<BR>\n" );
document.write( "        2 + 2s = 3s = 75<BR>\n" );
document.write( "                ---   ---<BR>\n" );
document.write( "                 3     3<BR>\n" );
document.write( "                  s = 25<BR>\n" );
document.write( "  85<BR>\n" );
document.write( " -25<BR>\n" );
document.write( "  ---<BR>\n" );
document.write( "  60 - 2(25) = 10   <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );