document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=508190>Question 508190</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having problems with recursive sequences (An= 3an-1), my secuence is 5,15,45,135... and im trying to make sure how to get 15 with these formula </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340887 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340887\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Your formula is correct. You just need to mention the first term A1 = 5.<BR>\n" );
document.write( "Then your formula says for the nth term in the sequence, An, you take the previous term A(n-1) and multiply it by 3.\r<BR>\n" );
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document.write( "So the first term is 5, then the second term is 5*3 = 15, then the third term is 15*3 = 45 and so on </SPAN>\n" );
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