document.write( "Question 507671: A man sold 2 acres more than 3/5 of his farm and had 4 acres less than 1/2 of it left. how many acres in the farm. \n" ); document.write( "
Algebra.Com's Answer #340829 by ankor@dixie-net.com(22740)\"\" \"About 
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A man sold 2 acres more than 3/5 of his farm and had 4 acres less than 1/2 of it left. how many acres in the farm.
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\n" ); document.write( "change the fractions to .6 and .5
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\n" ); document.write( "Let f = no. of acres in his farm
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\n" ); document.write( "f - (.6f+2) = .5f - 4
\n" ); document.write( "f - .6f - 2 = .5f - 4
\n" ); document.write( "f .6f - .5f = -4 + 2
\n" ); document.write( "-.1f = -2
\n" ); document.write( "f = \"%28-2%29%2F%28-.1%29\"
\n" ); document.write( "f = +20 acres originally in the farm
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\n" ); document.write( "See if that check out
\n" ); document.write( "20 - .6(20) - 2 = .5(20) - 4
\n" ); document.write( "20 - 12 - 2 = 10 - 4
\n" ); document.write( "6 = 6; confirms our solution of f = 20 \n" ); document.write( "
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