document.write( "Question 507904: how do i solve this problem,- The hundreds digit of a three-digit number is 2 more than the units digit. The digits of the original three-digit number are reversed, and the result is subtracted from the original three-digit number. What is the units digit of the result? Describe anything interesting you discover finding the solution. You need to try this out on at least three 3-digit numbers of your choosing. \n" ); document.write( "
Algebra.Com's Answer #340796 by josmiceli(19441)\"\" \"About 
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Call the digits a,b, and c
\n" ); document.write( "The number is abc
\n" ); document.write( "given:
\n" ); document.write( "a = c + 2
\n" ); document.write( "abc - cba
\n" ); document.write( "The units digit will be c - (c + 2) ,
\n" ); document.write( "but to do this, you have to carry
\n" ); document.write( "10 over to the c, and you have
\n" ); document.write( "10 + c - (c + 2) = 8
\n" ); document.write( "check:
\n" ); document.write( "abc = 553
\n" ); document.write( "cba = 355
\n" ); document.write( "553 - 355 = 198
\n" ); document.write( "---------------
\n" ); document.write( "abc = 917
\n" ); document.write( "cba = 719
\n" ); document.write( "917 - 719 = 198
\n" ); document.write( "---------------
\n" ); document.write( "abc = 391
\n" ); document.write( "cba = 193
\n" ); document.write( "391 - 193 = 198
\n" ); document.write( "---------------
\n" ); document.write( "The result is always 198
\n" ); document.write( "
\n" );