document.write( "Question 507904: how do i solve this problem,- The hundreds digit of a three-digit number is 2 more than the units digit. The digits of the original three-digit number are reversed, and the result is subtracted from the original three-digit number. What is the units digit of the result? Describe anything interesting you discover finding the solution. You need to try this out on at least three 3-digit numbers of your choosing. \n" ); document.write( "
Algebra.Com's Answer #340796 by josmiceli(19441) You can put this solution on YOUR website! Call the digits a,b, and c \n" ); document.write( "The number is abc \n" ); document.write( "given: \n" ); document.write( "a = c + 2 \n" ); document.write( "abc - cba \n" ); document.write( "The units digit will be c - (c + 2) , \n" ); document.write( "but to do this, you have to carry \n" ); document.write( "10 over to the c, and you have \n" ); document.write( "10 + c - (c + 2) = 8 \n" ); document.write( "check: \n" ); document.write( "abc = 553 \n" ); document.write( "cba = 355 \n" ); document.write( "553 - 355 = 198 \n" ); document.write( "--------------- \n" ); document.write( "abc = 917 \n" ); document.write( "cba = 719 \n" ); document.write( "917 - 719 = 198 \n" ); document.write( "--------------- \n" ); document.write( "abc = 391 \n" ); document.write( "cba = 193 \n" ); document.write( "391 - 193 = 198 \n" ); document.write( "--------------- \n" ); document.write( "The result is always 198 \n" ); document.write( " |