document.write( "Question 507740: The sum of the digits of a certain two certain numbers is 11 when reverse it's digits you increase the number number 45. \n" ); document.write( "

Algebra.Com's Answer #340706 by oberobic(2304) $\"\"$ $\"About$

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x + y = 11
\n" ); document.write( "x = 11-y
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\n" ); document.write( "10y + x = 10x+y+45
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\n" ); document.write( "10y + 11 -y = 10(11-y) + y + 45
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\n" ); document.write( "10y +11 -y = 110 -10y + y + 45
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\n" ); document.write( "9y + 11 = 155 -9y
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\n" ); document.write( "18y = 144
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\n" ); document.write( "y = 144/18
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\n" ); document.write( "y = 8
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\n" ); document.write( "x = 11-8
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\n" ); document.write( "x = 3
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\n" ); document.write( "So the original number was 38.
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\n" ); document.write( "If you reverse the digits, you have 83.
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\n" ); document.write( "38 + 45 = 83
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\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: The original number was 38.
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\n" ); document.write( "Done. \n" ); document.write( "

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