document.write( "Question 507710: How many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% solution to get a 40% solution? \r
\n" ); document.write( "\n" ); document.write( "I got the answer 13.3 L, but I'm not sure that it's right.
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Algebra.Com's Answer #340704 by oberobic(2304)\"\" \"About 
You can put this solution on YOUR website!
With mixture problems, you need to pay attention to how much 'pure' stuff you have and how much you need.
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\n" ); document.write( "40 liters of 50% solution means you have 20 liters of 'pure' alcohol
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\n" ); document.write( "x = liters of 10% solution is to be added until you have a final solution that is 40% alcohol.
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\n" ); document.write( ".5(40) + .1(x) = .4(40+x)
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\n" ); document.write( "multiply by 10 to remove decimals
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\n" ); document.write( "5(40) + x = 4(40+x)
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\n" ); document.write( "200 +x = 160 + 4x
\n" ); document.write( "40 = 3x
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\n" ); document.write( "x = 40/3 = 13 1/3 liters
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\n" ); document.write( "Check this to be sure it is the answer.
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\n" ); document.write( "40/3 * .1 = 4/3 liters of alcohol
\n" ); document.write( "120/3 * .5 = 20 liters of alcohol
\n" ); document.write( "= 21 1/3 liters of alcohol.
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\n" ); document.write( "40 + 40/3 = 120/3 + 40/3 = 160/3
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\n" ); document.write( "160/3*.4 = 64/3 = 21 1/3 liters of alcohol
\n" ); document.write( "which is correct.
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\n" ); document.write( "Answer: Add 13 1/3 liters of 10% alcohol solution.
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\n" ); document.write( "Done.
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