document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507739>Question 507739</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a rectangle has on side as 12 and another as x. and a different rectangle has 2-x as one side and 16 as another, find the value of x so that the rectangles have the same area.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340702 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area = Length * Width<BR>\n" );
document.write( "A = L*W<BR>\n" );
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document.write( "Rectangle 1:<BR>\n" );
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document.write( "L = 12<BR>\n" );
document.write( "W = x<BR>\n" );
document.write( "A = 12x<BR>\n" );
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document.write( "Rectangle 2:<BR>\n" );
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document.write( "L = 16<BR>\n" );
document.write( "W = 2-x<BR>\n" );
document.write( "A = 16(2-x)<BR>\n" );
document.write( "A = 32-16x<BR>\n" );
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document.write( "12x = 32-16x<BR>\n" );
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document.write( "-4x = 32<BR>\n" );
document.write( "x = -8<BR>\n" );
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document.write( "So this is impossible.<BR>\n" );
document.write( "You cannot have a negative width.<BR>\n" );
document.write( "There is something wrong with your problem statement.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );