document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507705>Question 507705</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8. The length of a rectangle is 3 meters more than its width. If the area is 108 square meters, what are the length and width? \r<BR>\n" );
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document.write( "OK I definetly need some help with these, please! \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340691 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340691\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width, so length is then x+3\r<BR>\n" );
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document.write( "Area = Length*Width\r<BR>\n" );
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document.write( "A = LW\r<BR>\n" );
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document.write( "108 = (x+3)*x\r<BR>\n" );
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document.write( "108 = x(x+3)\r<BR>\n" );
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document.write( "108 = x^2+3x\r<BR>\n" );
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document.write( "0 = x^2+3x-108\r<BR>\n" );
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document.write( "0 = (x-9)(x+12)\r<BR>\n" );
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document.write( "(x-9)(x+12)=0\r<BR>\n" );
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document.write( "x-9 = 0 or x+12 = 0 \r<BR>\n" );
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document.write( "x=9 or x=-12\r<BR>\n" );
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document.write( "Throw out the negative width to get x = 9\r<BR>\n" );
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document.write( "So the width is 9 meters and the length is 12 meters (since 9+3=12)\r<BR>\n" );
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document.write( "Let me know if you need more help or if you need me to explain a step in more detail.<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Jim  </SPAN>\n" );
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