document.write( "Question 51084: Anne and Nancy use a metal alloy that is 21.22% copper to make jewelry. How many ounces of a 16% alloy must be mixed with a 25% alloy to form 100 ounces of the desired alloy? \n" ); document.write( "
Algebra.Com's Answer #34066 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! SEE THE FOLLOWING EXAMPLES AND TRY.IF STILL IN DIFFICULTY PLEASE COME BACK \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "Ziggy's famous yogurt blends regular \n" ); document.write( "yogurt that is 3% fat with its no fat yogurt to obtain \n" ); document.write( "low fat yogurt that is 1% fat. How many pounds of \n" ); document.write( "regular and how many pounds of non-fat yogurt should \n" ); document.write( "be mixed to obtain 60 pounds of lowfat yogurt. \n" ); document.write( "PLEASE HELP ASAP. thank you \n" ); document.write( "THESE ARE MATERIAL BALANCE PROBLEMS.THE PRINCIPLE IS \n" ); document.write( "TO APPLY \n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.. \n" ); document.write( "THIS PRINCIPLE CAN BE APPLIED TO TOTAL MIXTURE AS A \n" ); document.write( "WHOLE AS WELL AS INDIVIDUAL COMPONENTS OF THE \n" ); document.write( "MIXTURE.LET US SEE THE APPLICATION USING YOUR PROBLEM. \n" ); document.write( "HERE THE MIXTURE COMPRISES 2 INPUTS-REGULAR YOGURT \n" ); document.write( "(RY) & NO FAT YOGURT (NFY) \n" ); document.write( "AND ONE OUT PUT-LOW FAT YOGURT (LFY).THE COMPONENT OF \n" ); document.write( "IMPORTANCE IN THE MIXTURE IS FAT CONTENT.SO WE TAKE 2 \n" ); document.write( "BALANCES HERE ..ONE FOR THE TOTAL MIXTURE AND ANOTHER \n" ); document.write( "FOR COMPONENT OF FAT IN THE MIXTURE. \n" ); document.write( "I..TOTAL BALANCE... \n" ); document.write( "INPUTS \n" ); document.write( "1.QTY.OF.RY=X POUNDS \n" ); document.write( "2.QTY OF NFY=Y POUNDS \n" ); document.write( "OUT PUT \n" ); document.write( "1.QTY.OF LFY=60 POUNDS \n" ); document.write( "SO APPLYING \n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET \n" ); document.write( "X+Y=60.............................I \n" ); document.write( "II..COMPONENT BALANCE..HERE IT IS FAT . \n" ); document.write( "INPUTS \n" ); document.write( "1.QTY.OF FAT IN RY=X*3/100=3X/100 POUNDS \n" ); document.write( "2.QTY OF FAT IN NFY=Y*0/100=0 POUNDS \n" ); document.write( "OUT PUT \n" ); document.write( "1.QTY.OF FAT IN LFY=60*1/100=60/100 POUNDS \n" ); document.write( "SO APPLYING \n" ); document.write( "TOTAL OF ALL INPUTS =TOTAL OF ALL OUTPUTS.....WE GET \n" ); document.write( "3X/100 + 0=60/100.............................II \n" ); document.write( "3X=60 \n" ); document.write( "X=20 \n" ); document.write( "Y=60-20=40 \n" ); document.write( "------------------------------------------------------------------- \n" ); document.write( "Mixture_Word_Problems/30587: The amount (by weight) of \n" ); document.write( "gold, silver and lead in three alloys of these metals \n" ); document.write( "are in ratios: \n" ); document.write( "4:3:2 - Alloy 1 \n" ); document.write( "3:5:1 - Alloy 2 \n" ); document.write( "2:2:5 - Alloy 3 \n" ); document.write( "It is desired to make a fourth alloy containing equal \n" ); document.write( "amounts of gold, silver and lead. How many grams each \n" ); document.write( "alloy should be used for every 10 grams of the new \n" ); document.write( "alloy? \n" ); document.write( "1 solutions \n" ); document.write( "Answer 17262 by venugopalramana(1167) About Me on \n" ); document.write( "2006-03-18 04:34:35 (Show Source): \n" ); document.write( "The amount (by weight) of gold, silver and lead in \n" ); document.write( "three alloys of these metals are in ratios: \n" ); document.write( "4:3:2 - Alloy 1 \n" ); document.write( "3:5:1 - Alloy 2 \n" ); document.write( "2:2:5 - Alloy 3 \n" ); document.write( "It is desired to make a fourth alloy containing equal \n" ); document.write( "amounts of gold, silver and lead. How many grams each \n" ); document.write( "alloy should be used for every 10 grams of the new \n" ); document.write( "alloy? \n" ); document.write( "LET X GMS OF ALLOY1 ,Y GMS OF ALLOY2 AND 10-X-Y GMS OF \n" ); document.write( "ALLOY3 BE USED TO GET \n" ); document.write( "X+Y+10-X-Y=10 GMS OF ALLOY 4 \n" ); document.write( "SO.................GOLD..............SIVER............LEAD \n" ); document.write( "IN THE MIX IS GIVEN BY \n" ); document.write( "X GMS \n" ); document.write( "A1...........4X/9..............3X/9..........2X/9 \n" ); document.write( "Y GMS \n" ); document.write( "A2...........3Y/9..............5Y/9...........Y/9.... \n" ); document.write( "10-X-Y GMS A3....(20-2X-2Y)/9 \n" ); document.write( "......(20-2X-2Y)/9...(50-5X-5Y)/9\r \n" ); document.write( "\n" ); document.write( "10 GMS \n" ); document.write( "A4.......(20+2X+Y)/9........(20+X+3Y)/9.....(50-3X-4Y)/9 \n" ); document.write( "THESE ARE ALL EQUAL...HENCE \n" ); document.write( "20+2X+Y = \n" ); document.write( "20+X+3Y...OR......................X-2Y=0..............I \n" ); document.write( "20+2X+Y = \n" ); document.write( "50-3X-4Y...OR...5X+5Y=30....OR....X+Y=6......II \n" ); document.write( "EQN.II - EQN I...GIVES \n" ); document.write( "X+Y-X+2Y=6......OR 3Y=6.....Y=2 \n" ); document.write( "SO X=6-Y=6-2=4 \n" ); document.write( "Z=10-4-2=4... \n" ); document.write( "HENCE 4 GMS OF A1,2 GMS OF A2 AND 4 GMS OF A3 ARE TO \n" ); document.write( "BE ADDED TO GET 10 GMS OF A4. \n" ); document.write( "-------------------------------------------------------------------------- \n" ); document.write( "How much pure alcohol must a nurse add to 8cc of a 70% \n" ); document.write( "solution to strengthen it to a 90% solution? Just need \n" ); document.write( "to know if this is right and if not what is right. \n" ); document.write( ".90(8)+ 0(x) = .70(x+8)....NO ...FIRST WRITE DOWN WHAT \n" ); document.write( "IS X?I THINK X IS QTY.OF \n" ); document.write( "PURE ALCOHOL TO BE ADDED TO 8 CC OF 70% ALCOHOL TO GET \n" ); document.write( "X+8 CC OF 90% SOLUTION.SO THE EQN. SHOULD BE \n" ); document.write( "X*100/100+8*70/100=(X+8)*90/100 \n" ); document.write( "7.2 = .70x+5.6.....X+5.6=0.9(X+8) \n" ); document.write( "1.6 = 70x.......X-0.9X=7.2-5.6=1.6 \n" ); document.write( "2.29c = x.......0.1X=1.6 \n" ); document.write( "..................OR X=1.6/0.1=16 CC. \n" ); document.write( "----------------------------------------------------\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |