document.write( "Question 507601: At noon you leave city X driving to city Y at 40mph. Two hours later your friend leaves city Y driving to city X at 60mph. The cities are 380 mile apart. What time do you meet? \n" ); document.write( "

Algebra.Com's Answer #340617 by josmiceli(19441) $\"\"$ $\"About$

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How much of a head start do you get?
\n" ); document.write( " $\"+d%5B1%5D+=+40%2A2+\"$
\n" ); document.write( " $\"+d%5B1%5D+=+80+\"$ mi
\n" ); document.write( "The distance between you is now $\"+380+-+80+=+300+\"$ mi
\n" ); document.write( "Start a stopwatch when your friend leaves- you both
\n" ); document.write( "will now travel for the same amount of time until you meet
\n" ); document.write( "Write both equations of motion:
\n" ); document.write( "For you:
\n" ); document.write( "(1) $\"+d+=+40%2At+\"$
\n" ); document.write( "For friend:
\n" ); document.write( "(2) $\"+300+-+d+=+60t+\"$
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) $\"+300+-+40t+=+60t+\"$
\n" ); document.write( "(2) $\"+100t+=+300+\"$
\n" ); document.write( "(2) $\"+t+=+3+\"$
\n" ); document.write( "You will meet a 5 o'clock ( 2 o'clock + 3 hrs )
\n" ); document.write( "check answer:
\n" ); document.write( "for you:
\n" ); document.write( "(1) $\"+d+=+40%2At+\"$
\n" ); document.write( "(1) $\"+d+=+40%2A3+\"$
\n" ); document.write( "(1) $\"+d+=+120+\"$
\n" ); document.write( "For friend:
\n" ); document.write( "(2) $\"+300+-+d+=+60t+\"$
\n" ); document.write( "(2) $\"+300+-+120+=+60t+\"$
\n" ); document.write( "(2) $\"+60t+=+180+\"$
\n" ); document.write( "(2) $\"+t+=+3+\"$
\n" ); document.write( "OK \n" ); document.write( "

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