document.write( "Question 507544: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width is 2 inches, it can support 2,000 pounds. How much weight can the same bea, support if it is turned so that the width is 8 inches?
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #340599 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
First write the equation of proportionality:
\n" ); document.write( "\"L+=+k%2Aw%2Ad%5E2%2Fl\" To find the value of k, the constant of proportionality, substitute the given values of: L = 2000, w = 2, d = 8, and l = 16
\n" ); document.write( "\"2000+=+k%2A2%2A8%5E2%2F16\" Solve for k. Multiply both sides by 16.
\n" ); document.write( "\"32000+=+k%2A128\" Divide by 128.
\n" ); document.write( "\"k+=+250\" so we can rewrite the first equation as:
\n" ); document.write( "\"L+=+250%2Aw%2Ad%5E2%2Fl6\" Now we can find the safe load, L, for the given parameters: w = 8, d = 2, and l = 16.
\n" ); document.write( "\"L+=+250%2A8%2A2%5E2%2F16\"
\n" ); document.write( "\"L+=+8000%2F16\"
\n" ); document.write( "\"L+=+500\"pounds.
\n" ); document.write( "
\n" );