document.write( "Question 51074This question is from textbook Applied College Algebra
\n" ); document.write( ": The height, in feet, of a rock,above the Colorado River that is thrown from the north rim of the Grand Canyon is given by Height = 5700 - 16t^2, where t is the number of seconds after the rock above the river 5 seconds after it is released. \n" ); document.write( "

Algebra.Com's Answer #34058 by Earlsdon(6294) $\"\"$ $\"About$

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It seems as though you might have missed part of the problem statement.
\n" ); document.write( "Do you have to find the height of the rock 5 seconds after it is dropped from the North Rim at a height of 5700 feet? Using the given function:
\n" ); document.write( " $\"h%28t%29+=+-16t%5E2%2B5700\"$ Substitute t = 5 and solve for h.
\n" ); document.write( " $\"h%285%29+=+-16%285%5E2%29%2B5700\"$
\n" ); document.write( " $\"h%285%29+=+-400%2B5700\"$
\n" ); document.write( " $\"h%285%29+=+5300\"$ feet.\r
\n" ); document.write( "\n" ); document.write( "The height of the rock would be 5300 feet five seconds after it was dropped from a height of 5700 feet.\r
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