document.write( "Question 505491: x^3-3x^2-4x+12=0 Please explain how to solve \n" ); document.write( "
Algebra.Com's Answer #340558 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! x^3-3x^2-4x+12=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^3-3x^2)+(-4x+12)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2(x-3)+(-4x+12)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2(x-3)-4(x-3)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x^2-4)(x-3)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(x-2)(x+2)(x-3)=0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-2 = 0, x+2 = 0, or x-3 = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 2, x = -2, or x = 3 \n" ); document.write( " |