document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507525>Question 507525</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the diameter of a circle is 3meters, what is the perimeter of the smallest<BR>\n" );
document.write( "square that can fully contain the circle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340514 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340514\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If you envision the square touching the circle at 4 points, with the circle inside the square, you can see that the dimensions of the square will be equal to the diameter of the circle. So, it will 3 meters on each side.<BR>\n" );
document.write( "The perimeter will be 4*3 = 12 m.<BR>\n" );
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document.write( "Since the perimeter of the square has to be greater than the circumference of the circle, you can check that.<BR>\n" );
document.write( "circumference = pi*d<BR>\n" );
document.write( " = 3*pi<BR>\n" );
document.write( " = 3*3.14, which is < 12.<BR>\n" );
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document.write( "Done. </SPAN>\n" );
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