document.write( "Question 507511: Please help me solve:\r
\n" ); document.write( "\n" ); document.write( "John is 4 years older than his sister, and 6 years ago he was twice his sisters age then. How old is each now?
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Algebra.Com's Answer #340509 by oberobic(2304)\"\" \"About 
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J = John's current age
\n" ); document.write( "S = John's sister's current age
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\n" ); document.write( "John is 4 years older than his sister
\n" ); document.write( "J = S+4
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\n" ); document.write( "6 years ago their ages were:
\n" ); document.write( "J-6
\n" ); document.write( "S-6
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\n" ); document.write( "6 years ago John was twice as old as his sister
\n" ); document.write( "J-6 = 2(S-6)
\n" ); document.write( "J = 2S -12 +6
\n" ); document.write( "J = 2S -6
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\n" ); document.write( "substitute
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\n" ); document.write( "J = S+4
\n" ); document.write( "2S -6 = S+4
\n" ); document.write( "S = 10
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\n" ); document.write( "J = S+4
\n" ); document.write( "J = 14
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\n" ); document.write( "Check the solution to be sure it is the answer.
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\n" ); document.write( "Six years ago...
\n" ); document.write( "J-6 = 8
\n" ); document.write( "S-6 = 4
\n" ); document.write( "8 = 2*4
\n" ); document.write( "Correct.
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\n" ); document.write( "Answer: John is 14 years old, and his sister is 10.
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\n" ); document.write( "Done.
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