document.write( "Question 507511: Please help me solve:\r
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document.write( "John is 4 years older than his sister, and 6 years ago he was twice his sisters age then. How old is each now? \n" );
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Algebra.Com's Answer #340509 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! J = John's current age \n" ); document.write( "S = John's sister's current age \n" ); document.write( ". \n" ); document.write( "John is 4 years older than his sister \n" ); document.write( "J = S+4 \n" ); document.write( ". \n" ); document.write( "6 years ago their ages were: \n" ); document.write( "J-6 \n" ); document.write( "S-6 \n" ); document.write( ". \n" ); document.write( "6 years ago John was twice as old as his sister \n" ); document.write( "J-6 = 2(S-6) \n" ); document.write( "J = 2S -12 +6 \n" ); document.write( "J = 2S -6 \n" ); document.write( ". \n" ); document.write( "substitute \n" ); document.write( ". \n" ); document.write( "J = S+4 \n" ); document.write( "2S -6 = S+4 \n" ); document.write( "S = 10 \n" ); document.write( ". \n" ); document.write( "J = S+4 \n" ); document.write( "J = 14 \n" ); document.write( ". \n" ); document.write( "Check the solution to be sure it is the answer. \n" ); document.write( ". \n" ); document.write( "Six years ago... \n" ); document.write( "J-6 = 8 \n" ); document.write( "S-6 = 4 \n" ); document.write( "8 = 2*4 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: John is 14 years old, and his sister is 10. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |