document.write( "Question 507450: How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference? \n" ); document.write( "
Algebra.Com's Answer #340491 by nerdybill(7384)\"\" \"About 
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How many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 10% antifreeze to get a mixture that is 50% difference?
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\n" ); document.write( "Let x = amount (gallons) of 60% antifreeze
\n" ); document.write( "then
\n" ); document.write( ".60x + .10(90) = .50(x+90)
\n" ); document.write( ".60x + 9 = .50x+45
\n" ); document.write( ".10x + 9 = 45
\n" ); document.write( ".10x = 36
\n" ); document.write( "x = 360 gallons\r
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