document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507495>Question 507495</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (5x-y) 3-(6-xy-6) : x=7, y=-1, z=-3<BR>\n" );
document.write( "How do I solve this problem </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340488 by </B><A HREF=/tutors/aboutme.mpl?userid=oberobic><B>oberobic(2304)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oberobic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340488\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Substitute the values and add up the parts.<BR>\n" );
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document.write( "I assume (5x-y)3 means (5x-y) times 3.<BR>\n" );
document.write( "(5*7 -(-1))*3 = 36*3<BR>\n" );
document.write( "36*3 = 108<BR>\n" );
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document.write( "(6-(7*(-1))-6) = 6+7-6<BR>\n" );
document.write( "6+7-6 = 7<BR>\n" );
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document.write( "108 -7 = 101<BR>\n" );
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document.write( "Note that 'z' was not listed as a variable in the problem. </SPAN>\n" );
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