document.write( "Question 507493: The breadth of a rectangle is one-third of its length. If the perimeter is 88cm find its dimensions \n" ); document.write( "

Algebra.Com's Answer #340486 by oberobic(2304) $\"\"$ $\"About$

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P = perimeter
\n" ); document.write( "P = 88 cm
\n" ); document.write( "L = length
\n" ); document.write( "W = width (also known as breadth)
\n" ); document.write( "P = 2(L+W)
\n" ); document.write( ".
\n" ); document.write( "W = 1/3L
\n" ); document.write( "so
\n" ); document.write( "L = 3W
\n" ); document.write( ".
\n" ); document.write( "substitute
\n" ); document.write( ".
\n" ); document.write( "2(3W+W) = 88
\n" ); document.write( "2(4W) = 88
\n" ); document.write( "8W = 88
\n" ); document.write( "W = 11
\n" ); document.write( ".
\n" ); document.write( "subsitute
\n" ); document.write( ".
\n" ); document.write( "L =3(W)
\n" ); document.write( "L = 33
\n" ); document.write( ".
\n" ); document.write( "Always check your solution to see if it is the answer.
\n" ); document.write( ".
\n" ); document.write( "P = 2L + 2W
\n" ); document.write( "2L = 66
\n" ); document.write( "2W = 22
\n" ); document.write( "66+22 = 88
\n" ); document.write( "Correct
\n" ); document.write( ".
\n" ); document.write( "Answer: The rectangle is 33 cm by 11 cm.
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\n" ); document.write( "Done. \n" ); document.write( "

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