document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507373>Question 507373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> one angle is three times its supplement increased by 68 degrees. Find the measure of the two supplementary angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340456 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340456\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> one angle is three times its supplement increased by 68 degrees.<BR>\n" );
document.write( " Find the measure of the two supplementary angles.<BR>\n" );
document.write( ":<BR>\n" );
document.write( "First find the angle (a)<BR>\n" );
document.write( "a = 3(180-a) + 68<BR>\n" );
document.write( "a = 540 - 3a + 68<BR>\n" );
document.write( "a + 3a = 540 + 68<BR>\n" );
document.write( "4a = 608<BR>\n" );
document.write( "a = 608/4<BR>\n" );
document.write( "a = 152 degrees is the angle<BR>\n" );
document.write( "then<BR>\n" );
document.write( "180 - 152 = 28 degrees is the supplement </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );