document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507382>Question 507382</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve for x.<BR>\n" );
document.write( "log (base 10)(x+3)=log(base 10) (2x) + log (base 10) (5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340453 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> solve for x.<BR>\n" );
document.write( "log (base 10)(x+3)=log(base 10) (2x) + log (base 10) (5)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "log (base 10)(x+3)-log(base 10) (2x) - log (base 10) (5)=0<BR>\n" );
document.write( "log (base 10)(x+3)-[log(base 10) (2x) + log (base 10) (5)]=0<BR>\n" );
document.write( "place under single log<BR>\n" );
document.write( "log[(x+3)/(2x*5)]=0<BR>\n" );
document.write( "log(x+3)/10x=0<BR>\n" );
document.write( "Convert to exponential form: base(10) raised to log of number(0)=number((x+3)/10x)<BR>\n" );
document.write( "10^0=(x+3)/10x=1<BR>\n" );
document.write( "10x=x+3<BR>\n" );
document.write( "9x=3<BR>\n" );
document.write( "x=1/3 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );