document.write( "Question 51069: A bicyclist rode into the country for 5h. In returning, her speed was 5 mi/h faster and the trip took 4h. What was her speed each way?\r
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\n" ); document.write( "\n" ); document.write( "R x T = D?????\r
\n" ); document.write( "\n" ); document.write( "I am not sure how to set this up and solve. Please help. Thank You. \n" ); document.write( "

Algebra.Com's Answer #34043 by mathchemprofessor(65) $\"\"$ $\"About$
You can put this solution on YOUR website!
Let the speed, the bicyclist rode for country in one way, be x miles per hour.
\n" ); document.write( "Time taken for one way was 5 hours.
\n" ); document.write( "So, the distance traveled = 5 hours*(xmph)=5x miles
\n" ); document.write( "On the reurn journey, the speed was (x+5)mph
\n" ); document.write( "Time taken=4hours
\n" ); document.write( "So, the distance traveled on his return=4hours*(x+5)mph=4(x+5)miles.
\n" ); document.write( "Since the distance traveled is the same both ways,
\n" ); document.write( "5x=4(x+5)
\n" ); document.write( "5x=4x+20
\n" ); document.write( "5x-4x=4x+20-4x
\n" ); document.write( "x=20
\n" ); document.write( "So, the speed in one way was 20mph and on his return,(20+5=)25mph
\n" ); document.write( "You can check the value of x by substituting in the equations.
\n" ); document.write( "The distance traveled in each way was 100 miles. \n" ); document.write( "

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