document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507336>Question 507336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me with this. I'm suppose to simplify and answer with only positive exponents (3/2)^8 (3/2)^-5 (3/2)^-4  I'm not sure what to do with the 3/2 am I raising to the power and then multipling them. I do know that with the (3/2) that have the negative exponents I flip them to (2/3) but I'm just not sure what to do with all of it together. Thank you for any help you can give. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340425 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> simplify and answer with only positive exponents <BR>\n" );
document.write( "(3/2)^8 (3/2)^-5 (3/2)^-4 <BR>\n" );
document.write( "----<BR>\n" );
document.write( "= (3/2)^(8-5-4)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "= (3/2)^(-1)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= 2/3<BR>\n" );
document.write( "============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );