document.write( "Question 507300: The sum of the ages of a woman and her son is 36 years. Six years from now the woman will be twice as old as her son. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #340411 by stanbon(75887)\"\" \"About 
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The sum of the ages of a woman and her son is 36 years. Six years from now the woman will be twice as old as her son. How old is each now?
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\n" ); document.write( "Equations:
\n" ); document.write( "w + s = 36
\n" ); document.write( "(w+6) = 2(s+6)
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\n" ); document.write( "Substitute for \"w\" and solve for \"s\":
\n" ); document.write( "36-s+6 = 2s+12
\n" ); document.write( "3s = 30
\n" ); document.write( "s = 10 yrs old (son's age now)
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\n" ); document.write( "Solve for \"w\":
\n" ); document.write( "w + s = 36
\n" ); document.write( "w + 10 = 36
\n" ); document.write( "w = 26 (mother's age now)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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