document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507092>Question 507092</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+log%28base+2%29++%286x%2B4%29=6++ ALIGN=MIDDLE  ALT=\"+log%28base+2%29++%286x%2B4%29=6++\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Please show me how to solve for x. Thanks. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340409 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log(base 2)  (6x+4)=6<BR>\n" );
document.write( "Convert to exponential form: base(2) raised to log of number(6)=number(6x+4)<BR>\n" );
document.write( "2^6=6x+4<BR>\n" );
document.write( "64=6x+4<BR>\n" );
document.write( "6x=60<BR>\n" );
document.write( "x=10 </SPAN>\n" );
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