document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507242>Question 507242</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary's age is 2/3 that of peter.2 years ago marys age was 1/2 of what petr age will be in5 years time,how old is peter know </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340383 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340383\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let<BR>\n" );
document.write( "Present of age of Mary = m<BR>\n" );
document.write( "Present of age of Peter = p\r<BR>\n" );
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document.write( "Mary's age is 2/3 that of Peter.<BR>\n" );
document.write( "m=2/3 * p<BR>\n" );
document.write( "m=2p/3 .............(1)\r<BR>\n" );
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document.write( "2 years ago means we have to subtract 2 from their present ages<BR>\n" );
document.write( "m-2=p-2<BR>\n" );
document.write( "then<BR>\n" );
document.write( "Mayr's age was 1/2<BR>\n" );
document.write( "m-2=1/2(p-2)<BR>\n" );
document.write( "of what Peter age will be in 5 years time means we have add 5 to age of Peter what was it 2 years ago<BR>\n" );
document.write( "m-2=1/2[(p-2)+5)]<BR>\n" );
document.write( "Multiply by 2 both sides of the equation<BR>\n" );
document.write( "2(m-2)=2*1/2[(p+5)-2)]<BR>\n" );
document.write( "2m-4=(p+5)-2)<BR>\n" );
document.write( "2m-4=p+5-2<BR>\n" );
document.write( "2m-4=p+3<BR>\n" );
document.write( "2m-p=3+4<BR>\n" );
document.write( "2m-p=7<BR>\n" );
document.write( "Put the value of m from (1)in above equation<BR>\n" );
document.write( "2(2p/3)-p=7<BR>\n" );
document.write( "(4p/3)-p=7<BR>\n" );
document.write( "Multiply by 3 both sides of the equation<BR>\n" );
document.write( "4p-3p=21<BR>\n" );
document.write( "p=21<BR>\n" );
document.write( "Put the value of p in (1)<BR>\n" );
document.write( "m=2p/3 .............(1)<BR>\n" );
document.write( "m=2(21)/3<BR>\n" );
document.write( "m=2*7<BR>\n" );
document.write( "m=14\r<BR>\n" );
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document.write( "Present of age of Mary = m = 14 years old<BR>\n" );
document.write( "Present of age of Peter = p = 21 years old\r<BR>\n" );
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document.write( "Check\r<BR>\n" );
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document.write( "Mary' age = 2/3 Peters age<BR>\n" );
document.write( "14 = 2/3 * 21<BR>\n" );
document.write( "14 = 42/3<BR>\n" );
document.write( "14 = 14<BR>\n" );
document.write( "2 years ago Mary's age = 14-2 = 12<BR>\n" );
document.write( "2 years ago Peter's age = 21-2 = 19<BR>\n" );
document.write( "after 5 years Peter's age = 19 + 5 = 24 which is twice the age of Mary or Mary's age 1/2 of the Peter. </SPAN>\n" );
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