document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507252>Question 507252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express the given quantity as a single logarithm.<BR>\n" );
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document.write( "1/9 ln(x + 2)^9 + 1/2[ln x &#8722; ln(x2 + 3x + 2)^2]\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340380 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340380\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Express the given quantity as a single logarithm.\r<BR>\n" );
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document.write( "1/9 ln(x + 2)^9 + 1/2[ln x &#8722; ln(x2 + 3x + 2)^2] \r<BR>\n" );
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document.write( "= ln[(x+2)^9]^(1/9) + ln(x^1/2) - ln(x^2+3x+2)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= ln(x+2) + ln(x^(1/2)) - ln(x^2+3x+2)<BR>\n" );
document.write( "----<BR>\n" );
document.write( "= ln[(x^(1/2)*(x+2)/(x^2+3x+2)]<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "= ln[x^(1/2)/(x+1)]<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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