document.write( "Question 507143: Nancy's dog is 3 times as old as Susie's dog. Both of their dog's ages equal 27. How old is Nancy's dog? \n" ); document.write( "
Algebra.Com's Answer #340357 by prathyu.2490(2)![]() ![]() ![]() You can put this solution on YOUR website! let nancy's dog age be 'N' \n" ); document.write( "let susie's dog age be 'S'\r \n" ); document.write( "\n" ); document.write( "\"Nancy's dog is 3 times as old as Susie's dog\"\r \n" ); document.write( "\n" ); document.write( "HENCE FROM THE ABOVE STATEMENT \n" ); document.write( " \n" ); document.write( "N=3S -> (1) \n" ); document.write( "\"Both of their dog's ages equal 27 MEANS\"\r \n" ); document.write( "\n" ); document.write( "N+S=27; -> (2)\r \n" ); document.write( "\n" ); document.write( "HENCE FROM (1) AND (2) SOLVE FOR N\r \n" ); document.write( "\n" ); document.write( "N=3S ->S=N/3;\r \n" ); document.write( "\n" ); document.write( "SUBSTITUTE THIS IN (2) \n" ); document.write( "->N+(N/3)=27 \n" ); document.write( "->4N/3=27; \n" ); document.write( "->N=20.25 YRS OR 20 1/4 YRS\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |