document.write( "Question 507143: Nancy's dog is 3 times as old as Susie's dog. Both of their dog's ages equal 27. How old is Nancy's dog? \n" ); document.write( "
Algebra.Com's Answer #340357 by prathyu.2490(2)\"\" \"About 
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let nancy's dog age be 'N'
\n" ); document.write( "let susie's dog age be 'S'\r
\n" ); document.write( "\n" ); document.write( "\"Nancy's dog is 3 times as old as Susie's dog\"\r
\n" ); document.write( "\n" ); document.write( "HENCE FROM THE ABOVE STATEMENT
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\n" ); document.write( "N=3S -> (1)
\n" ); document.write( "\"Both of their dog's ages equal 27 MEANS\"\r
\n" ); document.write( "\n" ); document.write( "N+S=27; -> (2)\r
\n" ); document.write( "\n" ); document.write( "HENCE FROM (1) AND (2) SOLVE FOR N\r
\n" ); document.write( "\n" ); document.write( "N=3S ->S=N/3;\r
\n" ); document.write( "\n" ); document.write( "SUBSTITUTE THIS IN (2)
\n" ); document.write( "->N+(N/3)=27
\n" ); document.write( "->4N/3=27;
\n" ); document.write( "->N=20.25 YRS OR 20 1/4 YRS\r
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