document.write( "Question 507144: Mary is 15 years old and her age is 5/16 of brother Pauls age. What is the difference in their ages? \n" ); document.write( "
Algebra.Com's Answer #340355 by prathyu.2490(2)![]() ![]() ![]() You can put this solution on YOUR website! mary age=15yrs \n" ); document.write( "let her brothers paul age be 'x' \n" ); document.write( "given \" her age is 5/16 of brother Pauls age\" \n" ); document.write( " \n" ); document.write( "therefore\r \n" ); document.write( "\n" ); document.write( "->15=(5*x)/16 \n" ); document.write( "->x=15*16/5 \n" ); document.write( "->x=48\r \n" ); document.write( "\n" ); document.write( "pauls age=x=48\r \n" ); document.write( "\n" ); document.write( "difference in their ages =(48-15)='33'\r \n" ); document.write( "\n" ); document.write( "therefore ans is '33' \n" ); document.write( " |