document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507147>Question 507147</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if the sum of the five consecutive integers is 40, what is the smallest of the five integers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340345 by </B><A HREF=/tutors/aboutme.mpl?userid=tinbar><B>tinbar(133)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tinbar><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340345\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the smallest. Then the next four consecutive integers are x+1, x+2, x+3, and x+4. Their sum is x + x+1 + x+2 + x+3 + x+4 = 5x+10\r<BR>\n" );
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document.write( "Now we know this 5x+10 = 40. 5x = 30. x = 6. Therefore x=6 is the smallest integer (and only integer) such that the next 4 numbers added together along with 6 is 40.  </SPAN>\n" );
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