document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=507078>Question 507078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Joe and Moe can mow the lawn in 26 minutes if they work together. If Moe works twice as fast as Joe, how long does it take Joe to mow the lawn alone?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340331 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340331\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Joe and Moe can mow the lawn in 26 minutes if they work together. If Moe works twice as fast as Joe, how long does it take Joe to mow the lawn alone?<BR>\n" );
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document.write( "Let J = time (minutes) Jo takes to mow alone<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2j = time Moe takes<BR>\n" );
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document.write( "26(1/J + 1/(2J)) = 1<BR>\n" );
document.write( "multiplying both sides by 2J:<BR>\n" );
document.write( "26(2 + 1) = 2J<BR>\n" );
document.write( "26(3) = 2J<BR>\n" );
document.write( "[26(3)]/2 = J<BR>\n" );
document.write( "[13(3)] = J<BR>\n" );
document.write( "39 minutes = J (Jo's time)<BR>\n" );
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