document.write( "Question 506904: 8.64 Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of
\n" ); document.write( "cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped
\n" ); document.write( "kernels were counted. There were 86. (a) Construct a 90 percent confidence interval for the proportion
\n" ); document.write( "of all kernels that would not pop. (b) Check the normality assumption. (c) Try the Very Quick
\n" ); document.write( "Rule. Does it work well here? Why, or why not? (d) Why might this sample not be typical?
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Algebra.Com's Answer #340303 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Biting an unpopped kernel of popcorn hurts! As an experiment, a self-confessed connoisseur of cheap popcorn carefully counted 773 kernels and put them in a popper. After popping, the unpopped kernels were counted. There were 86.
\n" ); document.write( "(a) Construct a 90 percent confidence interval for the proportion of all kernels that would not pop.
\n" ); document.write( "p-hat = 86/773 = 0.111..
\n" ); document.write( "E = 1.645*sqrt[(0.111)(0.889)/773]=0.0186
\n" ); document.write( "90% CI: 0.111-0.0186 < p < 0.111+0.0186
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\n" ); document.write( "(b) Check the normality assumption
\n" ); document.write( "I'll let you do that; it differs with every text.\r
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\n" ); document.write( "(c) Try the Very Quick Rule.
\n" ); document.write( "Does it work well here? Why, or why not?
\n" ); document.write( "I'm not sure what that is; it depends on your text.
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\n" ); document.write( "(d) Why might this sample not be typical?
\n" ); document.write( "The 773 is probably not a simple-random-sample
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \r
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