document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=506922>Question 506922</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angle 1 and 2 are supplementary angles<BR>\n" );
document.write( "m<1=(x-39)<BR>\n" );
document.write( "m<2=(x+6)<BR>\n" );
document.write( "find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340277 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340277\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "Supplementary angles are two angles that add to 180 degrees.\r<BR>\n" );
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document.write( "So  \r<BR>\n" );
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document.write( "m < 1 + m < 2 = 180\r<BR>\n" );
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document.write( "(x-39) + (x+6) = 180\r<BR>\n" );
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document.write( "x-39 + x+6 = 180\r<BR>\n" );
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document.write( "2x-33=180\r<BR>\n" );
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document.write( "2x=180+33\r<BR>\n" );
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document.write( "2x=213\r<BR>\n" );
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document.write( "x=213/2\r<BR>\n" );
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document.write( "x=106.5\r<BR>\n" );
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document.write( "---------------\r<BR>\n" );
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document.write( "m < 1 = (x-39) = 106.5 - 39 = 67.5\r<BR>\n" );
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document.write( "m < 2 = (x+6) = 106.5 + 6 = 112.5\r<BR>\n" );
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document.write( "So \r<BR>\n" );
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document.write( "m < 1 = 67.5\r<BR>\n" );
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document.write( "m < 2 = 112.5\r<BR>\n" );
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document.write( "Let me know if you need more help or if you need me to explain a step in more detail.<BR>\n" );
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document.write( "Thanks,\r<BR>\n" );
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document.write( "Jim  </SPAN>\n" );
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