document.write( "Question 506870: Suppose that the width of a certain rectangle is 2 inches less than its length. The area is numerically 8 less than twice the perimeter. Find the length and width of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #340264 by emargo19(101) $\"\"$ $\"About$

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Let w be the width
\n" ); document.write( "length= w+2
\n" ); document.write( "Area=w(w+2)\r
\n" ); document.write( "\n" ); document.write( "Perimeter=2(w)+2(w+2)-8\r
\n" ); document.write( "\n" ); document.write( " $\"%28w%2B2%29w=2%28w%29%2B2%28w%2B2%29-8\"$
\n" ); document.write( " $\"w%5E2%2B2w=2w%2B2w%2B4-8\"$
\n" ); document.write( " $\"w%5E2%2B2w=4w-4\"$
\n" ); document.write( " $\"w%5E2-2w%2B4=0\"$ \r
\n" ); document.write( "\n" ); document.write( "Next solve using Quadratic Formula.\r
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