document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=506700>Question 506700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate the function for the given value of x:\r<BR>\n" );
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document.write( "1.)  f(x) = 80-3x; f(5)\r<BR>\n" );
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document.write( "2.)  f(x) =  x(to the second power) + 4x -7; f(-1)\r<BR>\n" );
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document.write( "3.)  f(x) =  3|x-4| + 2; f(2) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340227 by </B><A HREF=/tutors/aboutme.mpl?userid=jennywecas><B>jennywecas(28)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jennywecas><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jennywecas><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340227\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1.)  f(x) = 80-3x; f(5)<BR>\n" );
document.write( "y=80-3(5)<BR>\n" );
document.write( "y=80-15<BR>\n" );
document.write( "y=65<BR>\n" );
document.write( "2.)  f(x) =  x(to the second power) + 4x -7; f(-1)<BR>\n" );
document.write( "y=-1*-1+4(-1)-7<BR>\n" );
document.write( "y=1-4-7<BR>\n" );
document.write( "y=-10<BR>\n" );
document.write( "3.)  f(x) =  3|x-4| + 2; f(2)<BR>\n" );
document.write( "y=3|2-4|<BR>\n" );
document.write( "y=3*2<BR>\n" );
document.write( "y=6 \r<BR>\n" );
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document.write( "btw if you need anymore help message me at jennywecas@yahoo.com </SPAN>\n" );
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