document.write( "Question 506544: CINDY IS MAKING A TRIP HOME FOR THANKSGIVING WHICH TAKES 8 HOURS ROUND TRIP. WITH THE HOLIDAY TRAFFIC, SHE AVERAGES 40 MILES AN HOUR ON THE WAY HOME AND 50 MILES AN HOUR ON THE WAY BACK TO SCHOOL. FIND THE TIME IT TOOK HER TO GET HOME AND THE TIME IT TOOK HER TO GET BACK TO SCHOOL. (USE THE FORMULA DISTANCE=RATE X TIME) \n" ); document.write( "
Algebra.Com's Answer #340185 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let distance from school to homebe x\r \n" ); document.write( "\n" ); document.write( "speed while going home= 40 mph \n" ); document.write( "time while going home = x/40 \n" ); document.write( ".. \n" ); document.write( "speed returning = 50 mph \n" ); document.write( "time returning = x/50\r \n" ); document.write( "\n" ); document.write( "Total time = time going + time returning \n" ); document.write( "8 = x/40 +x/50 \n" ); document.write( "LCD = 200 \n" ); document.write( "multiply by LCD \n" ); document.write( "200*8 = 5x+4x \n" ); document.write( "1600= 9x \n" ); document.write( "x= 177.7 ( round off)\r \n" ); document.write( "\n" ); document.write( "time going home = 178/40= 4.45 hours \n" ); document.write( "time returning = 178/50= 3.55 hours\r \n" ); document.write( "\n" ); document.write( "4.45 + 3.55 = 8 hours \n" ); document.write( "m.ananth@hotmail.com\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |