document.write( "Question 506547: At the beginning of a walk, Roberto and Juan are 7.7 miles apart. If they leave at the same time Roberto meets Juan in 11 hours. If they walk towards each other they meet in 1 hour. What are their average speeds?\r
\n" ); document.write( "\n" ); document.write( "I need to know how to set up these equations. I don't even know where to begin. \n" ); document.write( "
Algebra.Com's Answer #340181 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
at the same time Roberto meets Juan in 11 hours. If they walk towards each other they meet in 1 hour. What are their average speeds?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Roberto speed = x mph
\n" ); document.write( "Juan speed = y mph
\n" ); document.write( "let x>y
\n" ); document.write( "d= 7.7
\n" ); document.write( "if they go away then the catch up distance = 7.7
\n" ); document.write( "the catch up speed = x-y\r
\n" ); document.write( "\n" ); document.write( "t= d/r
\n" ); document.write( "t=11
\n" ); document.write( "11= 7.7/(x-y)
\n" ); document.write( "11x-11y=7.7
\n" ); document.write( "/11
\n" ); document.write( "x-y = 0.7..............1
\n" ); document.write( ".....
\n" ); document.write( "if they move towards
\n" ); document.write( "then speed = x+y
\n" ); document.write( "t=1
\n" ); document.write( "d= 7.7
\n" ); document.write( "t=d/r
\n" ); document.write( "1=7.7/(x+y)
\n" ); document.write( "x+y = 7.7 ------------2
\n" ); document.write( "add (1) & (2)
\n" ); document.write( "2x=0.7 + 7.7
\n" ); document.write( "2x=8.4
\n" ); document.write( "/2
\n" ); document.write( "x=4.2
\n" ); document.write( "Roberto speed = 4.2 mph
\n" ); document.write( "from (2) x+y =7.7
\n" ); document.write( "4.2+y=7.7
\n" ); document.write( "y=7.7-4.2
\n" ); document.write( "y=3.5
\n" ); document.write( "Juan speed = 3.5 mph\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( "
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