document.write( "Question 51040: If f(x) = (x - 2)^1/3, then f^-1(x) =\r
\n" ); document.write( "\n" ); document.write( " a. (x3 + 1)/2
\n" ); document.write( " b. (x3 - 1)/2
\n" ); document.write( " c. (x3 + 2)/2
\n" ); document.write( " d. (x3 - 2)/2
\n" ); document.write( " e. x3 - 2
\n" ); document.write( " f. x3 + 2
\n" ); document.write( " g. none of these
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Algebra.Com's Answer #34017 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
If \"f%28x%29+=+%28x-2%29%5E%281%2F3%29\", find \"f%5E-1%28x%29\"
\n" ); document.write( "First, replace f(x) with y, so now you have:
\n" ); document.write( "\"y+=+%28x-2%29%5E%281%2F3%29\" Cube both sides.
\n" ); document.write( "\"y%5E3+=+x-2\" Interchange the variables.
\n" ); document.write( "\"x%5E3+=+y-2\" Now solve for y.
\n" ); document.write( "\"y+=+x%5E3%2B2\" Finally, replace y with \"f%5E-1%28x%29\"
\n" ); document.write( "\"f%5E-1%28x%29+=+x%5E3%2B2\" This is choice f. in your list.\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "\"f%28f%5E-1%28x%29%29+=+f%28x%5E3%2B2%29\" = \"%28%28x%5E3%2B2%29-2%29%5E%281%2F3%29+=+%28x%5E3%29%5E%281%2F3%29\" = x
\n" ); document.write( "\"f%5E-1%28f%28x%29%29+=+f%5E-1%28x-2%29%5E%281%2F3%29\" = \"%28%28x%5E3%2B2%29-2%29%5E%281%2F3%29+=+%28x%5E3%29%5E%281%2F3%29\" = x\r
\n" ); document.write( "\n" ); document.write( "The above check is based on the following:
\n" ); document.write( "f(x) and g(x) are inverses of each other iff:
\n" ); document.write( "f(g(x)) = x for all x in the domain of g, and g(f(x)) = x for all x in the domain of f.
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