document.write( "Question 506378: The perimeter of a triangle is 124.
\n" ); document.write( "The first side is 6cm less than 3 times the second. The 3rd side is 10cm more than the second. what are the lengths of each side? \n" ); document.write( "
Algebra.Com's Answer #340126 by Sarah900(12)\"\" \"About 
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To solve this problem we need to write the side lengths in terms of a single variable. Since all the side lengths are compared to the second side, we will call the second side's length \"x\". So...
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\n" ); document.write( "Second length=x
\n" ); document.write( "first length= 3x-6
\n" ); document.write( "third length= x+10
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\n" ); document.write( "\n" ); document.write( "Since the perimeter of a triangle is equal to the length of all three sides we can add the three..\r
\n" ); document.write( "\n" ); document.write( "124= x+(x+10)+(3x-6)\r
\n" ); document.write( "\n" ); document.write( "Combine like terms and solve for x\r
\n" ); document.write( "\n" ); document.write( "124=5x+4
\n" ); document.write( "120=5x
\n" ); document.write( "24=x
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\n" ); document.write( "Now we know the length of the second side which we originally deemed x. To find the others you replace x with 24 in the other two.
\n" ); document.write( "3(24)-6=66
\n" ); document.write( "24+10=34 \n" ); document.write( "
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