document.write( "Question 505991: When Tim started football 3 years ago, his coach was twice his age. Currently, Tim's coach is 10 years older than him. How old is Tim now? \r
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Algebra.Com's Answer #340057 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Time = t
\n" ); document.write( "Present age of Coach= c\r
\n" ); document.write( "\n" ); document.write( "Three years ago means we have to subtract 3 from their current ages
\n" ); document.write( "c-3=t-3
\n" ); document.write( "Then
\n" ); document.write( "Coach was twice the age to time
\n" ); document.write( "c-3=2(t-3)
\n" ); document.write( "c-3=2t-6
\n" ); document.write( "c=2t-6+3
\n" ); document.write( "c=2t-3...........(1)
\n" ); document.write( "Tim's coach is 10 years older than him means if we add 10 to Tim's age Coach and Time will be of equal age
\n" ); document.write( "c=t+10.........(2)
\n" ); document.write( "Put the value of c from (2) to (1)
\n" ); document.write( "c=2t-3...........(1)
\n" ); document.write( "t+10=2t-3
\n" ); document.write( "t+10=2t-3
\n" ); document.write( "t=2t-3-10
\n" ); document.write( "t-2t=-13
\n" ); document.write( "-t=-13
\n" ); document.write( "Multiply by (-1) both sides of the equation
\n" ); document.write( "(-1)(-t)=(-1)(-13)
\n" ); document.write( "t=13
\n" ); document.write( "Put the value of t in (2)
\n" ); document.write( "c=t+10.........(2)
\n" ); document.write( "c=13+10
\n" ); document.write( "c=23
\n" ); document.write( "Present age of Time = t = 13
\n" ); document.write( "Present age of Coach= c = 23
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