document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=505988>Question 505988</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns 540 kilometers apart at the same time and travel toward each other. One car's rate is 16 kilometers per hour more than the other's. If they meet in 3  hours, what is the rate of the faster car? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340056 by </B><A HREF=/tutors/aboutme.mpl?userid=Gogonati><B>Gogonati(855)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Gogonati><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Gogonati><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340056\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let be x km/h the rate of the fastest car, then the rate of the slowest car will be x-16 km/h. The fastest car traveled 3x km and the slowest car traveled 3(x-16) km in the moment that they met each other. Since the distance between towns is<BR>\n" );
document.write( "540 km we write the equation:<BR>\n" );
document.write( "3x+3(x-16)=540, solving this equation we get x=98 km/h.<BR>\n" );
document.write( "Answer: The rate of the fastest car is 98 km/h. </SPAN>\n" );
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