document.write( "Question 505910: the sum of the digits of a three digit number is six. the ten digit is one less than the units digit and the number is twelve more than one hundred times the hundred digit
\n" ); document.write( "Find the three digits \n" ); document.write( "
Algebra.Com's Answer #340041 by htmentor(1343)\"\" \"About 
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the sum of the digits of a three digit number is six. the ten digit is one less than the units digit and the number is twelve more than one hundred times the hundred digit
\n" ); document.write( "Find the three digits
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\n" ); document.write( "Let h,t,u be the hundreds, tens and units digits
\n" ); document.write( "Given: sum of the digits = 6
\n" ); document.write( "h+t+u = 6
\n" ); document.write( "ten digit is one less than units digit
\n" ); document.write( "t = u - 1
\n" ); document.write( "number is 12 more than 100 times the hundred digit
\n" ); document.write( "The number can be expressed as 100h + 10t + u -> 100h + 10t + u = 100h + 12
\n" ); document.write( "The last equation gives 10t + u = 12
\n" ); document.write( "Substitute the value for t:
\n" ); document.write( "10(u - 1) + u = 12
\n" ); document.write( "11u = 22
\n" ); document.write( "u = 2
\n" ); document.write( "Therefore t = 1 and h = 6 - 2 - 1 = 3
\n" ); document.write( "Answer: 312\r
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