document.write( "Question 505891: Eric leaves ashville at the rate of 65 mph, bound for Madison. At the same time Beth leaves Madison at the rate of 55mph, bound for ashville. If the cities are 540 miles apart how long will it take eric and beth to meet? \n" ); document.write( "
Algebra.Com's Answer #340002 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
\n" ); document.write( "Let t=amount of time it takes for them to meet
\n" ); document.write( "Now we know that Eric and Beth will have met when their combined distances add up to 540 mi.\r
\n" ); document.write( "\n" ); document.write( "Distance Eric travels=65t
\n" ); document.write( "Distance Beth travels=55t
\n" ); document.write( "Sooooo:
\n" ); document.write( "65t+55t=540
\n" ); document.write( "120t=540
\n" ); document.write( "t=4.5 hr\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "Distance Eric travels=65*4.5=292.5 mi
\n" ); document.write( "Distance Beth travels=55*4.5=247.5 mi
\n" ); document.write( "292.5+247.5=540
\n" ); document.write( "540=540\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor\r
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