document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1160>Question 1160</A>: <I><SPAN STYLE=\"word-break: break-all;\">  Show how to find the domain, range, x and y intercepts, and any asymptotes<BR>\n" );
document.write( "for    <BR>\n" );
document.write( "G(x)= 1 +  2/(x-3)^2<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #340 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=340\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">       Since any denominator cannot be 0, <BR>\n" );
document.write( "      so x-3 cannot be 0 in y=G(x)= 1 +  2/(x-3)^2 and 3 should be<BR>\n" );
document.write( "      excluded from the domain of G.<BR>\n" );
document.write( "      Hence,the domain of G = R -{3} = (-oo,3) U(3,+oo)<BR>\n" );
document.write( "      Next,we see that 2/(x-3)^2 > 0 for all  real x, so G(x) > 1+0 = 1.<BR>\n" );
document.write( "      So, the range of G is (1, +oo)<BR>\n" );
document.write( "      <BR>\n" );
document.write( "      When x =0, G(0) = 1 + 2/9 = 11/9 is y-intercept.<BR>\n" );
document.write( "      Since y=G(x) >0 for all x, there are no x-intercepts of y=G(x).   \r<BR>\n" );
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document.write( "      The denominator in G(x) is x - 3= 0, which is a vertical asymptote <BR>\n" );
document.write( "      of G.<BR>\n" );
document.write( "      As x--> +oo, G(x) --> 1.So, a horizontal asymptote is y=1.<BR>\n" );
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