document.write( "Question 505296: A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimentions of the original rectangle? \n" ); document.write( "
Algebra.Com's Answer #339995 by lwsshak3(11628)\"\" \"About 
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A Rectangle is 4 times as long as it is wide. A second rectangle is 3 centimeters longer and 2 centimeters wider than the first. The area of the second rectangle is 530 square centimeters greater than the first. What are the dimentions of the original rectangle?
\n" ); document.write( "**
\n" ); document.write( "original rectangle:
\n" ); document.write( "let x=width
\n" ); document.write( "4x=length
\n" ); document.write( "area=x*4x=4x^2
\n" ); document.write( "..
\n" ); document.write( "2nd rectangle
\n" ); document.write( "x+2=width
\n" ); document.write( "4x+3=length
\n" ); document.write( "area=(x+2)(4x+3)=4x^2+11x+6
\n" ); document.write( "..
\n" ); document.write( "original area+530=2nd area
\n" ); document.write( "4x^2+530=4x^2+11x+6
\n" ); document.write( "11x+6=530
\n" ); document.write( "11x=530-6=524
\n" ); document.write( "x=524/11=47.64 cm
\n" ); document.write( "4x=190.55 cm
\n" ); document.write( "ans:
\n" ); document.write( "dimensions of original rectangle:
\n" ); document.write( "width=47.64 cm
\n" ); document.write( "length=190.55 cm \n" ); document.write( "
\n" );