document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=505585>Question 505585</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how to make 3^x=3 into logarithmic equation. please hurry! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #339987 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=339987\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how to make 3^x=3 into logarithmic equation. please hurry<BR>\n" );
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document.write( "3^x=3<BR>\n" );
document.write( "This is the exponential form of a logarithm which states that the base(3) raised to the logarithm of the number(x)=number(3).<BR>\n" );
document.write( "Logarithm form: log3(3)=x (log 3 to the base 3=x)<BR>\n" );
document.write( "In this case x=1<BR>\n" );
document.write( "So equation becomes log3(3)=1 (the logarithm of any base to its base is always=1) </SPAN>\n" );
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