document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=51028>Question 51028</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just don't understand these<BR>\n" );
document.write( "-2-4(2y-1)=(6-2y)3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33998 by </B><A HREF=/tutors/aboutme.mpl?userid=junior403><B>junior403(76)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=junior403><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33998\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> OK, no problem...<BR>\n" );
document.write( "Lets just take these one step at a time.<BR>\n" );
document.write( "-2-4(2y-1)=(6-2y)3<BR>\n" );
document.write( "What if we just work on one side of the equation at a time, that might help.<BR>\n" );
document.write( "So all we have is the left side:<BR>\n" );
document.write( "-2-4(2y-1)<BR>\n" );
document.write( "If we follow the order of operations we know that we should work with the parenthesis first using the distributive property, forget about the -2 for now. <BR>\n" );
document.write( "So we have...<BR>\n" );
document.write( "-4 X 2y and -4 X -1<BR>\n" );
document.write( "this becomes -8y and -4 or -8y -4<BR>\n" );
document.write( "ok so far?<BR>\n" );
document.write( "now if we bring back the -2 we have...<BR>\n" );
document.write( "-2 -8y -4 <BR>\n" );
document.write( "Does this make sense?<BR>\n" );
document.write( "Then we can combine like terms (the -2 and the -4)<BR>\n" );
document.write( "-8y -6 <BR>\n" );
document.write( "Ok?<BR>\n" );
document.write( "Now we put that aside and work on the right side of the equation...<BR>\n" );
document.write( "(6-2y)3 or we could look at this like 3(6-2y)<BR>\n" );
document.write( "So now we have...<BR>\n" );
document.write( "3 X 6 and 3 X -2y<BR>\n" );
document.write( "this becomes 18 and -6y or 18 - 6y<BR>\n" );
document.write( "ok so far?<BR>\n" );
document.write( "now that we have re-written the equation lets bring it back together...<BR>\n" );
document.write( "-8y -6 = 18 - 6y<BR>\n" );
document.write( "does this make sense?<BR>\n" );
document.write( "now we need to solve for y...<BR>\n" );
document.write( "we can combine like terms again accross the equals sign.<BR>\n" );
document.write( "In order to do that we can add 6 to both sides and we add 6y from both sides to make it look like this...<BR>\n" );
document.write( "-8y - 6 + 6 + 6y = 18 + 6 - 6y + 6y<BR>\n" );
document.write( "the 6's will cancel on the left side and the 6y's will cancel on the right.<BR>\n" );
document.write( "-8y + 6y = 18 + 6 <BR>\n" );
document.write( "now we can combine the terms...<BR>\n" );
document.write( "-2y = 24<BR>\n" );
document.write( "ok so far?<BR>\n" );
document.write( "now to completely isolate the y variable we can divide both sides by -2...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-2y%29%2F-2+=+24%2F-2 ALIGN=MIDDLE  ALT=\"%28-2y%29%2F-2+=+24%2F-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "the -2's cancel on the left side <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y+=+24%2F-2 ALIGN=MIDDLE  ALT=\"y+=+24%2F-2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "and we can reduce the right fraction to <BR>\n" );
document.write( "-12<BR>\n" );
document.write( "so our final answer is...<BR>\n" );
document.write( "y = -12<BR>\n" );
document.write( "I hope this helps.<BR>\n" );
document.write( "Please let me know if you have any more questions!<BR>\n" );
document.write( "Good Luck.<BR>\n" );
document.write( "Alan<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );