document.write( "Question 505755: I am twice as old as she was when I was as old as she is. when she is as old as I am now, the sum of our ages will be 63 \n" ); document.write( "
Algebra.Com's Answer #339970 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
I guess the question is \" How old are they now?\"
\n" ); document.write( "Let \"a\" = my age now
\n" ); document.write( "Let \"b\" = her age now
\n" ); document.write( "given:
\n" ); document.write( "The difference in their ages is always \"+a+-+b+\"
\n" ); document.write( "When I was \"b\" years old, how old was she?
\n" ); document.write( "She was \"+b+-+%28+a+-+b+%29++=+2b+-+a+\" yrs old
\n" ); document.write( "Now I am twice this age, or \"+4b+-+2a+\", so
\n" ); document.write( "\"+a+=+4b+-+2a+\"
\n" ); document.write( "(1) \"+3a+=+4b+\"
\n" ); document.write( "------------
\n" ); document.write( "When she is \"a\" yrs old, I will be \"+a+%2B+%28+a+-+b+%29+=+2a+-+b+\"
\n" ); document.write( "The sum of our ages is \"63\", so
\n" ); document.write( "\"+a+%2B+2a+-+b+=+63+\"
\n" ); document.write( "(2) \"+3a+-+b+=+63+\"
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+4b+-+b+=+63+\"
\n" ); document.write( "(2) \"+3b+=+63+\"
\n" ); document.write( "(2) \"+b+=+21+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+3a+=+4b+\"
\n" ); document.write( "(1) \"+a+=+4%2A21%2F+3\"
\n" ); document.write( "(1) \"+a+=+28+\"
\n" ); document.write( "I am 28 and she is 21
\n" ); document.write( "check answer:
\n" ); document.write( "When I was 21, she was 21 - (28 - 21) = 14
\n" ); document.write( "I am twice this age, or 28
\n" ); document.write( "----------------------
\n" ); document.write( "When she is as old as I am now, or 28, that will be in 28 - 21 = 7 years
\n" ); document.write( "and I will be 28 + 7 = 35, and the sum of our ages will be 28 + 35 = 63
\n" ); document.write( "OK\r
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