document.write( "Question 505745: factor:
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\n" ); document.write( "Im confused because its a quadratic...
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Algebra.Com's Answer #339960 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"4y%5E3%2B12y%5E2-y-3\" Start with the given expression\r
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\n" ); document.write( "\n" ); document.write( "\"%284y%5E3%2B12y%5E2%29%2B%28-y-3%29\" Group the terms in two pairs\r
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\n" ); document.write( "\n" ); document.write( "\"4y%5E2%28y%2B3%29-1%28y%2B3%29\" Factor out the GCF \"4y%5E2\" out of the first group. Factor out the GCF \"-1\" out of the second group\r
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\n" ); document.write( "\n" ); document.write( "\"%284y%5E2-1%29%28y%2B3%29\" Since we have the common term \"y%2B3\", we can combine like terms\r
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\n" ); document.write( "\n" ); document.write( "\"%282y-1%29%282y%2B1%29%28y%2B3%29\" Now factor \"4y%5E2-1\" to get \"%282y-1%29%282y%2B1%29\" (use the difference of squares formula)\r
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\n" ); document.write( "\n" ); document.write( "So \"4y%5E3%2B12y%5E2-y-3\" factors to \"%282y-1%29%282y%2B1%29%28y%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"4y%5E3%2B12y%5E2-y-3=%282y-1%29%282y%2B1%29%28y%2B3%29\"\r
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\n" ); document.write( "\n" ); document.write( "Let me know if you need more help or if you need me to explain a step in more detail.
\n" ); document.write( "Feel free to email me at jim_thompson5910@hotmail.com
\n" ); document.write( "or you can visit my website here: http://www.freewebs.com/jimthompson5910/home.html\r
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\n" ); document.write( "\n" ); document.write( "Thanks,\r
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\n" ); document.write( "\n" ); document.write( "Jim
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