document.write( "Question 505724: A coin collector has 31 dimes and nickels with a total face value of $2.40. (They are actually worth a lot more.) How many of each coin does she have? \n" ); document.write( "
Algebra.Com's Answer #339952 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! With money problems you have to keep track of the value of the coins and the number of coins. \n" ); document.write( "n = number of nickels \n" ); document.write( "5n = value \n" ); document.write( "d = number of dimes \n" ); document.write( "10d = value \n" ); document.write( ". \n" ); document.write( "n + d = 31 \n" ); document.write( "so \n" ); document.write( "n = 31-d \n" ); document.write( ". \n" ); document.write( "5n + 10d = 240 cents (which is easier than fooling with decimals) \n" ); document.write( ". \n" ); document.write( "substitute n = 31-d \n" ); document.write( ". \n" ); document.write( "5(31-d) +10d = 240 \n" ); document.write( "155 -5d +10d = 240 \n" ); document.write( "5d = 240-155 \n" ); document.write( "5d = 85 \n" ); document.write( "d = 17 \n" ); document.write( ". \n" ); document.write( "n = 31-17 \n" ); document.write( "n = 14 \n" ); document.write( ". \n" ); document.write( "Check using the values. \n" ); document.write( ". \n" ); document.write( "5(14) = 70 \n" ); document.write( "10(17) = 170 \n" ); document.write( "70+170 = 240 \n" ); document.write( "Correct. \n" ); document.write( ". \n" ); document.write( "Answer: The collector has 14 nickels and 17 dimes. \n" ); document.write( ". \n" ); document.write( "Done. \n" ); document.write( " |