document.write( "Question 505713: I have been given a word problem where all I know is that I have a total of 425 coins. there are 50 more nickles than pennies and there are 25 more dimes then nickles. I've been rocking my head about this problem all day and I cannot solve it. If you could solve and explain, I would much appreciate that. Thank you. \n" ); document.write( "
Algebra.Com's Answer #339943 by stanbon(75887)\"\" \"About 
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I have a total of 425 coins. there are 50 more nickles than pennies and there are 25 more dimes then nickles.
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\n" ); document.write( "Quantity Eq: p + n + d = 425 coins
\n" ); document.write( "Quantity Eq: n = p + 50
\n" ); document.write( "Quantity Eq: d = n + 25
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\n" ); document.write( "Substitute for \"p\" and for \"d\" and solve for \"n\":
\n" ); document.write( "(n-50) + n + (n+25) = 425
\n" ); document.write( "---
\n" ); document.write( "3n -25 = 425
\n" ); document.write( "3n = 450
\n" ); document.write( "n = 150 (# of nickels)
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\n" ); document.write( "p = n-50 = 100 (# of pennies)
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\n" ); document.write( "d = n+25 = 175 (# of dimes)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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